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作者 急需有关md5和java安全的资料(毕业设计用!)
yingxue6666





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于 2005-05-09 19:57 user profilesend a private message to usersearch all posts byselect and copy to clipboard. 
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我在做毕业设计的论文,急需有关md5和java安全的资料 ,拜托各位谁有帮个忙,我不盛感激!万分感激!


作者 Re:急需有关md5和java安全的资料(毕业设计用!) [Re:yingxue6666]
menzy



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发贴: 754
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于 2005-05-10 08:19 user profilesend a private message to usersearch all posts byselect and copy to clipboard. 
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在一些初始化处理后,MD5以512位分组来处理输入文本,每一分组又划分为16个32位子分组。算法的输出由四个32位分组组成,将它们级联形成一个128位散列值。
首先填充消息使其长度恰好为一个比512位的倍数仅小64位的数。填充方法是附一个1在消息后面,后接所要求的多个0,然后在其后附上64位的消息长度(填充前)。这两步的作用是使消息长度恰好是512位的整数倍(算法的其余部分要求如此),同时确保不同的消息在填充后不相同。
四个32位变量初始化为:
A=0x01234567
B=0x89abcdef
C=0xfedcba98
D=0x76543210
它们称为链接变量(chaining variable)
接着进行算法的主循环,循环的次数是消息中512位消息分组的数目。
将上面四个变量复制到别外的变量中:A到a,B到b,C到c,D到d。
主循环有四轮(MD4只有三轮),每轮很相拟。第一轮进行16次操作。每次操作对a,b,c和d中的其中三个作一次非线性函数运算,然后将所得结果加上第四个变量,文本的一个子分组和一个常数。再将所得结果向右环移一个不定的数,并加上a,b,c或d中之一。最后用该结果取代a,b,c或d中之一。
以一下是每次操作中用到的四个非线性函数(每轮一个)。
F(X,Y,Z)=(X&Y)|((~X)&Z)
G(X,Y,Z)=(X&Z)|(Y&(~Z))
H(X,Y,Z)=X^Y^Z
I(X,Y,Z)=Y^(X|(~Z))
(&是与,|是或,~是非,^是异或)
这些函数是这样设计的:如果X、Y和Z的对应位是独立和均匀的,那么结果的每一位也应是独立和均匀的。
函数F是按逐位方式操作:如果X,那么Y,否则Z。函数H是逐位奇偶操作符。
设Mj表示消息的第j个子分组(从0到15),<<<s表示循环左移s位,则四种操作为:
FF(a,b,c,d,Mj,s,ti)表示a=b+((a+(F(b,c,d)+Mj+ti)<<<s)
GG(a,b,c,d,Mj,s,ti)表示a=b+((a+(G(b,c,d)+Mj+ti)<<<s)
HH(a,b,c,d,Mj,s,ti)表示a=b+((a+(H(b,c,d)+Mj+ti)<<<s)
II(a,b,c,d,Mj,s,ti)表示a=b+((a+(I(b,c,d)+Mj+ti)<<<s)
这四轮(64步)是:
第一轮
FF(a,b,c,d,M0,7,0xd76aa478)
FF(d,a,b,c,M1,12,0xe8c7b756)
FF(c,d,a,b,M2,17,0x242070db)
FF(b,c,d,a,M3,22,0xc1bdceee)
FF(a,b,c,d,M4,7,0xf57c0faf)
FF(d,a,b,c,M5,12,0x4787c62a)
FF(c,d,a,b,M6,17,0xa8304613)
FF(b,c,d,a,M7,22,0xfd469501)
FF(a,b,c,d,M8,7,0x698098d8)
FF(d,a,b,c,M9,12,0x8b44f7af)
FF(c,d,a,b,M10,17,0xffff5bb1)
FF(b,c,d,a,M11,22,0x895cd7be)
FF(a,b,c,d,M12,7,0x6b901122)
FF(d,a,b,c,M13,12,0xfd987193)
FF(c,d,a,b,M14,17,0xa679438e)
FF(b,c,d,a,M15,22,0x49b40821)
第二轮
GG(a,b,c,d,M1,5,0xf61e2562)
GG(d,a,b,c,M6,9,0xc040b340)
GG(c,d,a,b,M11,14,0x265e5a51)
GG(b,c,d,a,M0,20,0xe9b6c7aa)
GG(a,b,c,d,M5,5,0xd62f105d)
GG(d,a,b,c,M10,9,0x02441453)
GG(c,d,a,b,M15,14,0xd8a1e681)
GG(b,c,d,a,M4,20,0xe7d3fbc8)
GG(a,b,c,d,M9,5,0x21e1cde6)
GG(d,a,b,c,M14,9,0xc33707d6)
GG(c,d,a,b,M3,14,0xf4d50d87)
GG(b,c,d,a,M8,20,0x455a14ed)
GG(a,b,c,d,M13,5,0xa9e3e905)
GG(d,a,b,c,M2,9,0xfcefa3f8)
GG(c,d,a,b,M7,14,0x676f02d9)
GG(b,c,d,a,M12,20,0x8d2a4c8a)
第三轮
HH(a,b,c,d,M5,4,0xfffa3942)
HH(d,a,b,c,M8,11,0x8771f681)
HH(c,d,a,b,M11,16,0x6d9d6122)
HH(b,c,d,a,M14,23,0xfde5380c)
HH(a,b,c,d,M1,4,0xa4beea44)
HH(d,a,b,c,M4,11,0x4bdecfa9)
HH(c,d,a,b,M7,16,0xf6bb4b60)
HH(b,c,d,a,M10,23,0xbebfbc70)
HH(a,b,c,d,M13,4,0x289b7ec6)
HH(d,a,b,c,M0,11,0xeaa127fa)
HH(c,d,a,b,M3,16,0xd4ef3085)
HH(b,c,d,a,M6,23,0x04881d05)
HH(a,b,c,d,M9,4,0xd9d4d039)
HH(d,a,b,c,M12,11,0xe6db99e5)
HH(c,d,a,b,M15,16,0x1fa27cf8)
HH(b,c,d,a,M2,23,0xc4ac5665)
第四轮
II(a,b,c,d,M0,6,0xf4292244)
II(d,a,b,c,M7,10,0x432aff97)
II(c,d,a,b,M14,15,0xab9423a7)
II(b,c,d,a,M5,21,0xfc93a039)
II(a,b,c,d,M12,6,0x655b59c3)
II(d,a,b,c,M3,10,0x8f0ccc92)
II(c,d,a,b,M10,15,0xffeff47d)
II(b,c,d,a,M1,21,0x85845dd1)
II(a,b,c,d,M8,6,0x6fa87e4f)
II(d,a,b,c,M15,10,0xfe2ce6e0)
II(c,d,a,b,M6,15,0xa3014314)
II(b,c,d,a,M13,21,0x4e0811a1)
II(a,b,c,d,M4,6,0xf7537e82)
II(d,a,b,c,M11,10,0xbd3af235)
II(c,d,a,b,M2,15,0x2ad7d2bb)
II(b,c,d,a,M9,21,0xeb86d391)
常数ti可以如下选择:
在第i步中,ti是4294967296*abs(sinLight Bulb)的整数部分,i的单位是弧度。
(2的32次方)
所有这些完成之后,将A,B,C,D分别加上a,b,c,d。然后用下一分组数据继续运行算法,最后的输出是A,B,C和D的级联。

MD5的安全性

MD5相对MD4所作的改进:
1.增加了第四轮.
2.每一步均有唯一的加法常数.
3.为减弱第二轮中函数G的对称性从(X&Y)|(X&Z)|(Y&Z)变为(X&Z)|(Y&(~Z))
4.第一步加上了上一步的结果,这将引起更快的雪崩效应.
5.改变了第二轮和第三轮中访问消息子分组的次序,使其更不相似.
6.近似优化了每一轮中的循环左移位移量以实现更快的雪崩效应.各轮的位移量互不相同.



作者 Re:急需有关md5和java安全的资料(毕业设计用!) [Re:yingxue6666]
menzy



版主


发贴: 754
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于 2005-05-10 08:20 user profilesend a private message to usersearch all posts byselect and copy to clipboard. 
ie only, sorry for netscape users:-)add this post to my favorite list
source

MD5.java (15.6k)



作者 Re:急需有关md5和java安全的资料(毕业设计用!) [Re:yingxue6666]
menzy



版主


发贴: 754
积分: 113
于 2005-05-10 08:21 user profilesend a private message to usersearch all posts byselect and copy to clipboard. 
ie only, sorry for netscape users:-)add this post to my favorite list
用以下几个信息对你做出来的程序作一个简单的测试,看看程序有没有错误。

   MD5 ("") = d41d8cd98f00b204e9800998ecf8427e
   MD5 ("a") = 0cc175b9c0f1b6a831c399e269772661
   MD5 ("abc") = 900150983cd24fb0d6963f7d28e17f72
   MD5 ("message digest") = f96b697d7cb7938d525a2f31aaf161d0
   MD5 ("abcdefghijklmnopqrstuvwxyz") = c3fcd3d76192e4007dfb496cca67e13b
   MD5 ("ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789") =
d174ab98d277d9f5a5611c2c9f419d9f
   MD5 ("123456789012345678901234567890123456789012345678901234567890123456789
01234567890") = 57edf4a22be3c955ac49da2e2107b67a



作者 Re:急需有关md5和java安全的资料(毕业设计用!) [Re:menzy]
yingxue6666





发贴: 13
积分: 0
于 2005-05-10 21:43 user profilesend a private message to usersearch all posts byselect and copy to clipboard. 
ie only, sorry for netscape users:-)add this post to my favorite list
谢谢版主,请问版主是不是很了解MD5?我可以再次请教你吗?


作者 Re:急需有关md5和java安全的资料(毕业设计用!) [Re:menzy]
YuLimin

简单就是美

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于 2005-05-11 08:10 user profilesend a private message to usersearch all posts byselect and copy to clipboard. 
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MD5的算法程序:
http://www.cjsdn.net/post/view?bid=30&id=140693&sty=1



 当兵不后悔!后悔不当兵! 
超越黎明时空,追逐时代潮流!
人,是要靠自己的!简单就是美!
我的Java:http://www.Java2Class.net
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作者 Re:急需有关md5和java安全的资料(毕业设计用!) [Re:yingxue6666]
yingxue6666





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于 2005-06-01 11:26 user profilesend a private message to usersearch all posts byselect and copy to clipboard. 
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我设计中有一个MD5.JAVA里面的代码如下:
package yang;

public class MD5
{
  String hex_chr = "0123456789abcdef";
  private String rhex(int num)
  {
    String str = "";
    for(int j = 0; j <= 3; j++)
    str = str + hex_chr.charAt((num >> (j * 8 + 4)) & 0x0F) + hex_chr.charAt((num >> (j * 8)) & 0x0F);
    return str;
  }

  private int[] str2blks_MD5(String str)
  {
    int nblk = ((str.length() + 8) >> 6) + 1;
    int[] blks = new int[nblk * 16];
    int i = 0;
    for(i = 0; i < nblk * 16; i++) {
      blks[i] = 0;
    }
    for(i = 0; i < str.length(); i++) {
      blks[i >> 2] |= str.charAtLight Bulb << ((i % 4) * 8);
    }
    blks[i >> 2] |= 0x80 << ((i % 4) * 8);
    blks[nblk * 16 - 2] = str.length()*8;

    return blks;
  }

  private int add(int x, int y)
  {
    return ((x&0x7FFFFFFF) + (y&0x7FFFFFFF)) ^ (x&0x80000000) ^ (y&0x80000000);
  }

  private int rol(int num, int cnt)
  {
    return (num << cnt) | (num >>> (32 - cnt));
  }

  private int cmn(int q, int a, int b, int x, int s, int t)
  {
    return add(rol(add(add(a, q), add(x, t)), s), b);
  }
  private int ff(int a, int b, int c, int d, int x, int s, int t)
  {
    return cmn((b & c) | ((~b) & d), a, b, x, s, t);
  }
  private int gg(int a, int b, int c, int d, int x, int s, int t)
  {
    return cmn((b & d) | (c & (~d)), a, b, x, s, t);
  }
  private int hh(int a, int b, int c, int d, int x, int s, int t)
  {
    return cmn(b ^ c ^ d, a, b, x, s, t);
  }
  private int ii(int a, int b, int c, int d, int x, int s, int t)
  {
    return cmn(c ^ (b | (~d)), a, b, x, s, t);
  }

  public String calcMD5(String str)
  {
  int[] x = str2blks_MD5(str);
  int a = 0x67452301;
  int b = 0xEFCDAB89;
  int c = 0x98BADCFE;
  int d = 0x10325476;

  for(int i = 0; i < x.length; i += 16)
  {
  int olda = a;
  int oldb = b;
  int oldc = c;
  int oldd = d;

  a = ff(a, b, c, d, x[i+ 0], 7 , 0xD76AA478);
  d = ff(d, a, b, c, x[i+ 1], 12, 0xE8C7B756);
  c = ff(c, d, a, b, x[i+ 2], 17, 0x242070DBlack Eye;
  b = ff(b, c, d, a, x[i+ 3], 22, 0xC1BDCEEE);
  a = ff(a, b, c, d, x[i+ 4], 7 , 0xF57C0FAF);
  d = ff(d, a, b, c, x[i+ 5], 12, 0x4787C62A);
  c = ff(c, d, a, b, x[i+ 6], 17, 0xA8304613);
  b = ff(b, c, d, a, x[i+ 7], 22, 0xFD469501);
  a = ff(a, b, c, d, x[i+ 8], 7 , 0x69809Cool8);
  d = ff(d, a, b, c, x[i+ 9], 12, 0x8B44F7AF);
  c = ff(c, d, a, b, x[i+10], 17, 0xFFFF5BB1);
  b = ff(b, c, d, a, x[i+11], 22, 0x895CD7BE);
  a = ff(a, b, c, d, x[i+12], 7 , 0x6B901122);
  d = ff(d, a, b, c, x[i+13], 12, 0xFD987193);
  c = ff(c, d, a, b, x[i+14], 17, 0xA679438E);
  b = ff(b, c, d, a, x[i+15], 22, 0x49B40821);

  a = gg(a, b, c, d, x[i+ 1], 5 , 0xF61E2562);
  d = gg(d, a, b, c, x[i+ 6], 9 , 0xC040B340);
  c = gg(c, d, a, b, x[i+11], 14, 0x265E5A51);
  b = gg(b, c, d, a, x[i+ 0], 20, 0xE9B6C7AA);
  a = gg(a, b, c, d, x[i+ 5], 5 , 0xD62F105D);
  d = gg(d, a, b, c, x[i+10], 9 , 0x02441453);
  c = gg(c, d, a, b, x[i+15], 14, 0xD8A1E681);
  b = gg(b, c, d, a, x[i+ 4], 20, 0xE7D3FBC8);
  a = gg(a, b, c, d, x[i+ 9], 5 , 0x21E1CDE6);
  d = gg(d, a, b, c, x[i+14], 9 , 0xC33707D6);
  c = gg(c, d, a, b, x[i+ 3], 14, 0xF4D50D87);
  b = gg(b, c, d, a, x[i+ 8], 20, 0x455A14ED);
  a = gg(a, b, c, d, x[i+13], 5 , 0xA9E3E905);
  d = gg(d, a, b, c, x[i+ 2], 9 , 0xFCEFA3F8);
  c = gg(c, d, a, b, x[i+ 7], 14, 0x676F02D9);
  b = gg(b, c, d, a, x[i+12], 20, 0xCool2A4C8A);

  a = hh(a, b, c, d, x[i+ 5], 4 , 0xFFFA3942);
  d = hh(d, a, b, c, x[i+ 8], 11, 0x8771F681);
  c = hh(c, d, a, b, x[i+11], 16, 0x6D9D6122);
  b = hh(b, c, d, a, x[i+14], 23, 0xFDE5380C);
  a = hh(a, b, c, d, x[i+ 1], 4 , 0xA4BEEA44);
  d = hh(d, a, b, c, x[i+ 4], 11, 0x4BDECFA9);
  c = hh(c, d, a, b, x[i+ 7], 16, 0xF6BB4B60);
  b = hh(b, c, d, a, x[i+10], 23, 0xBEBFBC70);
  a = hh(a, b, c, d, x[i+13], 4 , 0x289B7EC6);
  d = hh(d, a, b, c, x[i+ 0], 11, 0xEAA127FA);
  c = hh(c, d, a, b, x[i+ 3], 16, 0xD4EF3085);
  b = hh(b, c, d, a, x[i+ 6], 23, 0x04881D05);
  a = hh(a, b, c, d, x[i+ 9], 4 , 0xD9D4D039);
  d = hh(d, a, b, c, x[i+12], 11, 0xE6DB99E5);
  c = hh(c, d, a, b, x[i+15], 16, 0x1FA27CF8);
  b = hh(b, c, d, a, x[i+ 2], 23, 0xC4AC5665);

  a = ii(a, b, c, d, x[i+ 0], 6 , 0xF4292244);
  d = ii(d, a, b, c, x[i+ 7], 10, 0x432AFF97);
  c = ii(c, d, a, b, x[i+14], 15, 0xAB9423A7);
  b = ii(b, c, d, a, x[i+ 5], 21, 0xFC93A039);
  a = ii(a, b, c, d, x[i+12], 6 , 0x655B59C3);
  d = ii(d, a, b, c, x[i+ 3], 10, 0x8F0CCC92);
  c = ii(c, d, a, b, x[i+10], 15, 0xFFEFF47D);
  b = ii(b, c, d, a, x[i+ 1], 21, 0x85845DD1);
  a = ii(a, b, c, d, x[i+ 8], 6 , 0x6FA87E4F);
  d = ii(d, a, b, c, x[i+15], 10, 0xFE2CE6E0);
  c = ii(c, d, a, b, x[i+ 6], 15, 0xA3014314);
  b = ii(b, c, d, a, x[i+13], 21, 0x4E0811A1);
  a = ii(a, b, c, d, x[i+ 4], 6 , 0xF7537E82);
  d = ii(d, a, b, c, x[i+11], 10, 0xBD3AF235);
  c = ii(c, d, a, b, x[i+ 2], 15, 0x2AD7D2BBlack Eye;
  b = ii(b, c, d, a, x[i+ 9], 21, 0xEB86D391);

  a = add(a, olda);
  b = add(b, oldb);
  c = add(c, oldc);
  d = add(d, oldd);
  }
  return rhexAngel + rhexBeer + rhexCoffee + rhexFood;
  }
  public static void main(String[] args)
  {
    MD5 md = new MD5();
    String str = md.calcMD5("123456");
    System.out.println(str);
  }
}
但是我不知道每句的意思,请高手们给我指点,写一下注释,留下联系方式,小女子万分感谢了!



作者 Re:急需有关md5和java安全的资料(毕业设计用!) [Re:yingxue6666]
yingxue6666





发贴: 13
积分: 0
于 2005-06-01 11:30 user profilesend a private message to usersearch all posts byselect and copy to clipboard. 
ie only, sorry for netscape users:-)add this post to my favorite list
怎么代码有的地方变成图了片,唉



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