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Re:请教：怎样理解“函数的重载”？ [Re:WWWLS]

bluecrystal

发贴: 2788991
积分: 48

于 2005-10-02 20:50

Java supports method name overloading so that multiple methods can share the same name. For example, suppose you are writing a class that can render various types of data (strings, integers, and so on) to its drawing area. You need to write a method that knows how to render each data type. In other languages, you have to think of a new name for each method, for example, drawString, drawInteger, drawFloat, and so on. In Java, you can use the same name for all of the drawing methods but pass a different type of parameter to each method. So, in your data rendering class, you can declare three methods named draw, each of which takes a different type of parameter:
class DataRenderer {
void draw(String s) {
. . .
}
void draw(int i) {
. . .
}
void draw(float f) {
. . .
}
}

Overloaded methods are differentiated by the number and type of the arguments passed into the method. In the code sample, draw(String s) and draw(int i) are distinct and unique methods because they require different argument types. You cannot declare more than one method with the same name and the same number and type of arguments because the compiler cannot differentiate them. So, draw(String s) and draw(String t) are identical and result in a compiler error.

这是java tutorial 里面关于overload(重载)的描述，请仔细阅读一下

切记不要和override(覆盖)相混淆

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话题树型展开

人气	标题	作者	字数	发贴时间
9763	请教：怎样理解“函数的重载”？	WWWLS	996	2005-10-02 18:15
7497	Re:请教：怎样理解“函数的重载”？	bluecrystal	1376	2005-10-02 20:50
8059	Re:请教：怎样理解“函数的重载”？	ranchgirl	794	2005-10-02 21:52
7448	Re:请教：怎样理解“函数的重载”？	ranchgirl	134	2005-10-02 22:03
8421	Re:请教：怎样理解“函数的重载”？	bluecrystal	2554	2005-10-02 22:31

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